### A x.ray photon of wavelength 1.82 exponent-10m is scattered at angle θ.if fractional change in wavelength is 2% then what is value of scattering angle?

A x.ray photon of wavelength 1.82 exponent-10m is scattered
at angle θ.if fractional change in wavelength is 2% then what is value of
scattering angle?

**Data:**

λ = 1.82 x 10

^{-10 }m
Δ λ / λ = 2%

θ = ?

**Solution:**

According to Compton’s Shift we can write as

Δ λ =(h / mo c) ( 1- Cos θ) ----------(1)

Finding Δ λ

Δ λ = 2 % x λ

Δ λ = 2 /100 x 1.82 x 10

^{-10}= 3.64 x 10^{-12}m
Now using equation (1)

1- Cos θ = Δ λ x mo c
/h

or

Cos θ = 1- (Δ λ x mo c /h) = 1 – (3.64 x 10

^{-12}x 3 x 10^{8}x 9.1 x 10^{-31}/ 6.63 x 10^{-34})=-0.4988
Or

θ=Cos-1 (-0.4988) =

**120**Answer^{0}
## Comments

## Post a Comment