First Law of Thermodynamics & Its Applications
Statement, mathematical formulation, sign conventions, and step-by-step application to Isobaric, Isochoric, Isothermal, and Adiabatic processes.
1. Statement & Mathematical Form
Alternative Definition: When heat energy ($\Delta Q$) is supplied to a system, it is utilized in two parts: to change the internal energy of the system ($\Delta U$) and to perform external work by the system ($\Delta W$).
$$\Delta Q = \Delta U + \Delta W$$
Or since work done at constant pressure is $\Delta W = P \Delta V$: $$\Delta Q = \Delta U + P \Delta V$$
Sign Conventions
- $\Delta Q$ is Positive ($+$): When heat is supplied to the system.
- $\Delta Q$ is Negative ($-$): When heat is rejected by the system.
- $\Delta W$ is Positive ($+$): When work is done by the system (Expansion).
- $\Delta W$ is Negative ($-$): When work is done on the system (Compression).
- $\Delta U$ is Positive ($+$): When temperature/internal energy increases.
- $\Delta U$ is Negative ($-$): When temperature/internal energy decreases.
2. Four Applications of the First Law
1. Isobaric Process ($P = \text{Constant}$)
A thermodynamic process in which external pressure remains constant.
Supplied heat energy increases internal energy and performs work to move the piston:
$$\Delta W = F \cdot \Delta x = (P A) \cdot \Delta x = P \Delta V$$Substituting into the First Law gives:
$$\Delta Q_p = \Delta U + P \Delta V$$Outcome: Heat supplied at constant pressure equals the change in total enthalpy of the system.
2. Isochoric Process ($V = \text{Constant}$)
A thermodynamic process in which the volume of the system remains fixed.
Since the piston remains fixed, there is no change in volume ($\Delta V = 0$):
$$\Delta W = P \Delta V = P(0) = 0$$Substituting into the First Law gives:
$$\Delta Q_v = \Delta U$$Outcome: All heat supplied goes directly toward increasing the internal energy (and temperature) of the system.
3. Isothermal Process ($T = \text{Constant}$)
A thermodynamic process conducted at constant temperature (Boyle's Law holds valid: $P \propto 1/V$).
Since internal energy depends solely on temperature for an ideal gas, $\Delta T = 0$ implies $\Delta U = 0$:
$$\Delta Q = 0 + \Delta W$$ $$\Delta Q = \Delta W$$Outcome: All heat supplied to the system is entirely converted into external mechanical work.
4. Adiabatic Process ($\Delta Q = 0$)
A process in which no heat enters or leaves the system ($\Delta Q = 0$). Temperature does not remain constant.
Substituting $\Delta Q = 0$ into the First Law gives:
$$0 = \Delta U + \Delta W$$ $$\Delta W = -\Delta U \quad \text{or} \quad \Delta U = -\Delta W$$Outcome: Work done by the gas during expansion comes at the expense of its own internal energy, causing cooling.
- Isobaric: $\Delta Q = \Delta U + P\Delta V$
- Isochoric: $\Delta Q = \Delta U$
- Isothermal: $\Delta Q = \Delta W$
- Adiabatic: $\Delta W = -\Delta U$
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